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How many molecules are there in 1.76 kg of hydrazine, N_2H_4? 1.76 times 10^26 3

ID: 1068586 • Letter: H

Question

How many molecules are there in 1.76 kg of hydrazine, N_2H_4? 1.76 times 10^26 3.31 times 10^25 5.50 times 10^23 2.92 times 10^21 1.88 times 10^22 The species that has the same number of neutrons as 37 17 CI is 35 17 CL 31 15 P 32 16 S. 40 18 Ar. What is the mass in grams of one propene, C_3H_6. molecule? 2.53 times 10^25 g 6.99 times 10^-23 g 44.0 g 1.99 times 10^23 42.0 g What is the symbol of the nuclide having 15 protons and 16 neutrons? 31 15 P 15 16 S 31 15 S 16 15 P 16 15 S What is the formula for calcium nitride? CaNO_2 Ca(NO_3)_2 Ca(NO_2)_3 Ca_2N_3 Ca_3N_2

Explanation / Answer

12. molar mass of hydrazine = 32 g/mol

1.76 kg = 1760 g

number of molecules in 32 g of hydrazine = 6.023*1023 molecules

Number of molecules in 1760 g of hydrazine = (6.023*1023 molecules/32 g)*1760 g = 331*1023 molecules = 3.31*1025 molecules

Correct option is B.

13. Number of neutrons in 3717Cl is = 37-17 = 20

Number of neutrons in 3616S = 36-16 = 20

So, Option C is correct.

14. Molar mass of propene = 42 g/mol

Number of molecules in 42 g of propene = 6.023*1023 molecules

mass of 1 molecule = (42 g/6.023*1023 molecules) = 6.99*10-23 molecules

Option B is correct.

15. Number of protons = 15

So, subscript in symbol will be 15.

Number of neutrons = 16

Atomic mass of element = 15+16 = 31

So, superscript in symbol will be 31.

Element P has 15 protons and S has 16 protons. So, correct symbol is 3115P.

Option A is correct.

16. Calcium nitride is Ca3N2.

Option E is correct.

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