Calculate the G °\' for each reaction using the equation G °\' = - nF E 0\' and

Question

Calculate the G°' for each reaction using the equation G°' = -nFE0' and the values for E0' given in Table 1. Show your work.

Table 1. Reduction potentials for reduction half reactions:

1/2 O2 +2H+ +2e- H2O -------------> E0' = +0.82 V
fumarate + 2H+ + 2e- succinate -------------> E0' = +0.03 V

oxaloacetate + 2H+ + 2e- malate -------------> E0' = -0.17 V
pyruvate + 2H+ + 2e- lactate -------------> E0' = -0.19 V

-ketoglutarate + CO2 + 2H+ + 2e- isocitrate -------------> E0' = -0.38 V

FAD + 2H+ + 2e- FADH2 -------------> E0' = -0.22 V
NAD+ +2H+ +2e- NADH+H+ -------------> E0' = -0.32 V
CoQ + 2H+ + 2e- CoQH2 -------------> E0' = +0.06 V

Problem: FADH2 + CoQ FAD + CoQH2

Explanation / Answer

    Problem: FADH2 + CoQ FAD + CoQH2

FADH2 ----------------> FAD + 2H+ + 2e- E0 = 0.22V

CoQ + 2H+ + 2e- CoQH2                           E0' = +0.06 V

-------------------------------------------------------------------------------------

FADH2 + CoQ FAD + CoQH2                 E0 cell = 0.28V

   n= 2

G°' = -nFE0

        = -2*96500*0.28

      = -54040J

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