Splitting of a signal in a proton NMR spectrum tells us the number of chemically

Question

Splitting of a signal in a proton NMR spectrum tells us the number of chemically non-equivalent hydrogens in the immediate vicinity of the hydrogen giving the signal. Predict the number of lines exhibited by hydrogens at the labeled positions in a first-order NMR spectrum. (Make the approximation that all coupling constants are equal.) The number of lines exhibited by hydrogen(s) a is. The number of lines exhibited by hydrogen(s) b is. The number of lines exhibited by hydrogen(s) c is. The number of lines exhibited by hydrogen(s) a is. The number of lines exhibited by hydrogen(s) b is. The number of lines exhibited by hydrogen(s) c is .

Explanation / Answer

no. of peak = n + 1 where, n = no. of hydrogen on nabouring carbon atom.

1)

Number of line exibited by Hydrogen a is = 1

because naboring corbon have 0 hydrogen

Number of line exibited by Hydrogens b is = 4

because naboring corbon have 3 hydrogen

Number of line exibited by Hydrogens c is = 3

because naboring corbon have 2 hydrogen

2)

Number of line exibited by Hydrogens a is = 2

because naboring corbon have 1 hydrogen

Number of line exibited by Hydrogen b is = 5

because naboring corbon have 3 hydrogen of -CH3 and 1 hydrogen of =C - H

Number of line exibited by Hydrogen c is = 2

because naboring corbon have 1 hydrogen

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