Splitting of a signal in a proton NMR spectrum tells us the number of chemically

Question

Splitting of a signal in a proton NMR spectrum tells us the number of chemically non-equivalent hydrogens in the immediate vicinity of the hydrogen giving the signal. Predict the number of lines exhibited by hydrogens at the labeled positions in a first-order NMR spectrum. (Make the approximation that all coupling constants are equal) CH2 The number of lines exhibited by hydrogen(s) a is The number of lines exhibited by hydrogen(s) b is The number of lines exhibited by hydrogen(scis b c The number of lines exhibited by hydrogen(s) a is The number of lines exhibited by hydrogen(s) b is The number of lines exhibited by hydrogen(s) c is 8 more group attempts remaining Retry Entire Group Submit Answer

Explanation / Answer

Number of line denoted by hydrogen = n + 1 where, n = number of hydrogen on nabouring carbons atom

#

1) number of lines exibited by hydrogen(s) a is = 2

Because nabouring carbon have 1 proton

  number of lines exibited by hydrogen(s) b is = 7

Because nabouring carbon have 6 proton

number of lines exibited by hydrogen(s) c is = 1

Because nabouring is O and donot have proton

2)

number of lines exibited by hydrogen(s) a is = 8

Because nabouring carbon have 7 proton

  number of lines exibited by hydrogen(s) b is = 4

Because nabouring carbon have 3 proton

number of lines exibited by hydrogen(s) c is = 2

Because nabouring carbon have 1 proton

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1) number of lines exibited by hydrogen(s) a is = 1

Because nabouring carbon have 0 proton

  number of lines exibited by hydrogen(s)b is = 3

Because nabouring carbon have 2 proton

number of lines exibited by hydrogen(s) c is = 6

Because nabouring carbon have 5 proton

2)

number of lines exibited by hydrogen(s) a is = 2

Because nabouring carbon have 1 proton

  number of lines exibited by hydrogen(s) b is = 6

Because nabouring carbon have 5 proton

number of lines exibited by hydrogen(s) c is = 5

Because nabouring carbon have 4 proton

#

1) number of lines exibited by hydrogen(s) a is = 7

Because nabouring carbon have 6 proton

  number of lines exibited by hydrogen(s) b is = 4

Because nabouring carbon have 3 proton

number of lines exibited by hydrogen(s) c is = 3

Because nabouring carbon have 2 proton

2)

number of lines exibited by hydrogen(s) a is = 2

Because nabouring carbon have 1 proton

  number of lines exibited by hydrogen(s) b is = 6

Because nabouring carbon have 5 proton

number of lines exibited by hydrogen(s) c is = 2

Because nabouring carbon have 1 proton

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