What would be the line-bond structure, for (CH_3)_3CCH_2CH(CH_3)_3? What is the

Question

What would be the line-bond structure, for (CH_3)_3CCH_2CH(CH_3)_3? What is the IUPAC name of the following? 5-ethyl-6-methyheptane 2, 3 diethylhexptane 4-ethyl-3-methyloctane 4-ethyl-3-methyheptane The boiling point of n-butane (-0.4 degree C) higher than isobutane (-10.2 degree C) is because isobutane has weaker intermolecular van der Waals forces. stronger intermolecular van der Waals forces. weaker dipole-dipole attractive forces. stronger dipole-dipole attractive forces. The heats of combustion (delta H^+) of heptane and 3, 3-dimethypentane are 4, 817 and 4, 609 kJ/mol, respectively. Which statement is true? Heptane is 8 kJ/mol more stable then 3, 3-dimethylpentane. 3, 3 Dimethylpentane is 8 kJ/mol more stable than heptane. Stabilities cannot be compared since they are not isomers. Stabilities cannot be compared since they give different combustion products. How many moles of O_2 gas would be consumed in the complete combustion of 0.250mole of C_5H_12. 0.250 mole O_2 1.000 mole O_2 0.800 mole O_2 2.00 mole O_2 The carbon-carbon single bond in the following is formed by the overlap of which two orbitals? H_2C = CH-C identicalto N sp-sp sp^2 -sp sp^2 -sp^2 sp^2 -sp^3

Explanation / Answer

12) The line bond structure of (CH3)3CCH2CH (CH3)2 is option B (The name of this hydrocarbon is 2,2,4-trimethylpentane. It is an isomer of octane)

13) The IUPAC name of the compound is Option C (4-ethyl-3-methyloctane)

Explanation- longest carbon chain of 8 carbon atom, one methyl group is attached to third carbon atom and one ethyl group is attached to forth carbon atom. So the name of compound is 4-ethyl-3-methyloctane.

14) The boiling point of n-butane (0.4 °C) is higher than Isobutane (10.2 °C) because Isobutane has weaker Van der Waals intermolecular forces. Option A

Explanation- Isobutane has branched structure. So there are lower Van der Waals (dispersion) forces .In the straight chain butane, as the straight chains can get closer together. The stronger intermolecular forces give a higher boiling point.

15)

The heats of combustion (-H0) of heptane and 3,3-dimethypentane are 4,817 and 4,809 kJ/mole

respectively.

Statement B (3, 3-Dimethylpentane is 8 kJ/mole more stable then heptane) is true.

16)

C5H12 + 8O2 --> 5CO2 + 6H2O

1 mole pentane needed 8 moles of O2

So, 0.250 moles of pentane needed 8 x 0.252/1 = 2 moles of O2

Option D is correct.

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