Complete and balance the following redox equation using the set of smallest whol

Question

Complete and balance the following redox equation using the set of smallest whole-number coefficients. Now sum the coefficients of all species in the balanced equation. (Remember the coefficients that are equal to one.) The sum of the coefficients is BrO_3 -(aq) + Sb^3+(aq) rightarrow Br^-(aq) + Sb^5+(aq) (acidic solution) 4. 12. 13. 17. None of these. Which one of the following reagents is capable of oxidizing Br^- (aq) to Br_2(l) under standard-state conditions? I^- (aq) NO_3^- (aq) Ag^+ (aq) Al^3+ (aq) Au^3+(aq) Determine the cell diagram for the reaction below. Assume a platinum electrode is used when no other solid is present. 2Fe^2+ (aq) + Pb^2+ (aq) rightarrow 2Fe^3+ (aq) + Pb(s) Pt(s) | Fe^2+ (aq), Fe^3+ (aq) || Pb^2+ (aq) | Pb(s) Pb(s) | Pb^2+ (aq) || Fe^2+ (aq), Fe^3+ (aq) | Pt(s) Pt(s) | Fe^3+ (aq), Fe^2+ (aq) || Pb(s) | Pb^2+ (aq) | Pt(s) Pt(s) | Pb^2+ (aq) | Pb(s) || Fe^2+ (aq), Fe^3+ (aq) | Pt(s) Pt(s) Fe^2+ (aq), Pb62+ (aq) || Fe^3+ (aq) | Pb(s) Complete and balance the following redox equation. What is the coefficient of H_2O when the equation is balanced using smallest whole-number coefficients? MnO_4^- + SO^2-_3 rightarrow Mn^2+ + SO^2+_4 (acidic solution) 3 4 5 8 None of these. Which of the following concentration cells will produce the highest E_Cell? Zn(s) | Zn^2+ (0.10M) || Zn(s) | zn^2+ (1.0M) Cu^2+ (0.01M) | Cu(s) || cu(s) | cu^2+ (0.10M) Zn(s) | Zn^2+ 90.3M0 || Zn^2+ 93.0M) | Zn(s) Fe(s) | Fe62= (0.2M) || Fe^2+ (2.0M) | Fe(s) They will all produce the same E_Cell.

Explanation / Answer

Q1.

use redox equations to balance this in acidic:

split half cells:

BrO3 = Br-

Sb+3 = Sb+5

balance O adding H2O

BrO3- = Br- + 3H2O

Sb+3 = Sb+5

balance H adding H+

6H+ + BrO3- = Br- + 3H2O

Sb+3 = Sb+5

balance charges

6e- + 6H+ + BrO3- = Br- + 3H2O

Sb+3 = Sb+5 + 2e-

balance e-

6e- + 6H+ + BrO3- = Br- + 3H2O

3Sb+3 = 3Sb+5 + 6e-

add all

3Sb+3 + 6e- + 6H+ + BrO3- = Br- + 3H2O+ 3Sb+5 + 6e-

cancel terms

3Sb+3 +6H+ + BrO3- = Br- + 3H2O+ 3Sb+5

sum of coefficients:

3+6+1+1+3+3 = 17

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