Complete and balance the following redox equation. Br2 ? BrO3- + Br- (basic solu

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sol First, break the equation into two half reactions and balance the principle atom (you may have to reduce the overall equation later): Br2 --> 2 Br- Br2 --> 2 BrO3- Next balance oxygens by adding water to any side that needs oxygens: Br2 --> 2 Br- 6 H2O + Br2 --> 2 BrO3- Next, balance hydrogens by adding H+ ions to the sides that need them: so Br2 --> 2 Br- we hve 6 H2O + Br2 --> 2 BrO3- + 12 H+ then Next, balance charges by adding electrons to one side of each equation: 2e- + Br2 --> 2 Br- so 6 H2O + Br2 --> 2 BrO3- + 12 H+ + 10 e- Now, we multiply the two equations by some small numbers so that the number of electrons in the two half reactions cancel: 10 e- + 5 Br2 --> 10 Br- 6 H2O + Br2 --> 2 BrO3- + 12 H+ + 10 e- then Add the two reactions and then reduce it, if you can: 6 H2O + 6 Br2 --> 10 Br- + 2 BrO3- + 12 H+ 3 H2O + 3 Br2 --> 5 Br- + BrO3- + 6 H+ and you're balanced. ans

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