The following is the result of measuring reaction rate constant of a chemical re

Question

The following is the result of measuring reaction rate constant of a chemical reaction A rightarrow P, according to each temperature. A and P are both at liquid sate, and volume change caused by the reaction is ignored. The previous reaction is to be proceeded at 500K isothermal. The chemical reaction A rightarrow P is known to be elementary reaction, whose reaction rate equation can be expressed as^-r A = -kC_A. The purpose is to convert 95% of A into P, using CSTR. If in-flow rate is v_0 = 100 L/sec, calculate the required volume of CSTR.. Suppose the same reaction is to be proceeded in PFR. Calculate the required volume of PFR if every other condition remains the same.

Explanation / Answer

At 500 K, the rate constant = 15.029

The rate of reaction is,

rA = kCA = 15.029

CSTR:

Initial conc = 100 M

Final conc = 5 M

Equation for CSTR is as follows:

V/V0 = (CA0 - CA ) / rA

V / 100 = (100 - 5) / 15.029 x5

V = 126.4 L

3)

PFR:

V/V0 = 1/k ln (CA0 / CA )

V = (100 / 15.029) x ln (100/5)

= 19.93 L

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