What is the molarity of a solution that contains 45.5 g NaNO3 in 125.0 mL water?

Question

What is the molarity of a solution that contains 45.5 g NaNO3 in 125.0 mL water? How many grams of Ca(OH)2 are needed to make 100.0 mL of 0.250 M solution? If 45 mL of a 0.133 M NaOH solution is diluted to 450 mL, what is the new molarity? From the titration graph, pH at equivalence= ___, volume of base at equivalence=_____ The titration graph shows 10.0 mL H2SO4 titrated with 0.20 M NaOH. Molarity of acid=
What is the pH of 0.0001 M HNO3? 4.0 What is the pH of 0.01 M KOH? 12 What is the pH of a 0.01 M HF ( 1% dissociation)
Circle the conjugate acid: CH3NH2 + H2O CH3NH3+ + OH-
Circle the acid that exists mainly as a molecule not as ions: HBr, HI, HF, HCI
A salt-water solution is likely to boil at ... A.) 100 C B.)98 C C.) 104 C
Circle the Solution(1M) with the highest boiling point: Ca3N2 (aq) , K3N(aq), Na2S(aq), PF5(aq) Circle the Solution (1M) with the highest freezing point: NaCI(aq), SF4(aq), AlBr3(aq), HI(aq)
According to the graph which compound is the most soluble at 10 degrees Celsius? How many g KNO3 form a saturated solution in 300 g of water at 40 degrees Celsius ? If 65g of KCI are stirred in 100g of water at 80 degrees Celsius, how many grams don’t dissolve?



What is the molarity of a solution that contains 45.5 g NaNO3 in 125.0 mL water? How many grams of Ca(OH)2 are needed to make 100.0 mL of 0.250 M solution? If 45 mL of a 0.133 M NaOH solution is diluted to 450 mL, what is the new molarity? From the titration graph, pH at equivalence= ___, volume of base at equivalence=_____ The titration graph shows 10.0 mL H2SO4 titrated with 0.20 M NaOH. Molarity of acid=
What is the pH of 0.0001 M HNO3? 4.0 What is the pH of 0.01 M KOH? 12 What is the pH of a 0.01 M HF ( 1% dissociation)
Circle the conjugate acid: CH3NH2 + H2O CH3NH3+ + OH-
Circle the acid that exists mainly as a molecule not as ions: HBr, HI, HF, HCI
A salt-water solution is likely to boil at ... A.) 100 C B.)98 C C.) 104 C
Circle the Solution(1M) with the highest boiling point: Ca3N2 (aq) , K3N(aq), Na2S(aq), PF5(aq) Circle the Solution (1M) with the highest freezing point: NaCI(aq), SF4(aq), AlBr3(aq), HI(aq)
According to the graph which compound is the most soluble at 10 degrees Celsius? How many g KNO3 form a saturated solution in 300 g of water at 40 degrees Celsius ? If 65g of KCI are stirred in 100g of water at 80 degrees Celsius, how many grams don’t dissolve?



What is the molarity of a solution that contains 45.5 g NaNO3 in 125.0 mL water? How many grams of Ca(OH)2 are needed to make 100.0 mL of 0.250 M solution? If 45 mL of a 0.133 M NaOH solution is diluted to 450 mL, what is the new molarity? From the titration graph, pH at equivalence= ___, volume of base at equivalence=_____ The titration graph shows 10.0 mL H2SO4 titrated with 0.20 M NaOH. Molarity of acid=
What is the pH of 0.0001 M HNO3? 4.0 What is the pH of 0.01 M KOH? 12 What is the pH of a 0.01 M HF ( 1% dissociation)
Circle the conjugate acid: CH3NH2 + H2O CH3NH3+ + OH-
Circle the acid that exists mainly as a molecule not as ions: HBr, HI, HF, HCI
A salt-water solution is likely to boil at ... A.) 100 C B.)98 C C.) 104 C
Circle the Solution(1M) with the highest boiling point: Ca3N2 (aq) , K3N(aq), Na2S(aq), PF5(aq) Circle the Solution (1M) with the highest freezing point: NaCI(aq), SF4(aq), AlBr3(aq), HI(aq)
According to the graph which compound is the most soluble at 10 degrees Celsius? How many g KNO3 form a saturated solution in 300 g of water at 40 degrees Celsius ? If 65g of KCI are stirred in 100g of water at 80 degrees Celsius, how many grams don’t dissolve?

Explanation / Answer

Ans1 :

Number of moles of NaNO3 = 45.5 / 85 = 0.535 mol

Molarity = no. of moles of NaNO3 / volume of solution in L

M = 0.535 / 0.125

M = 4.28 M

So the molarity of the solution will be 4.28 M

Ans 2 :

Molarity = no. of moles / volume of solution in L

0.250 = n / 0.100

n = 0.025 mol

Mass of Ca(OH)2 = 0.025 x molar mass

= 0.025 x 74.093

= 1.85 grams

Ans 3 :

Using the formula M1 V1 = M2 V2 ,

where M is molarity and V is volume

putting all the values we get :

0.133 x 45 = M2 x 450

M2 = 0.0133 M

Ans 4 : Graph is required to calculate the pH at equivalence point and the volume of base

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