3· The expression for the electrostatic potential energy between two charged obj

Question

3· The expression for the electrostatic potential energy between two charged objects is V(r) = k442/r, where q1 and q2 are the charges on the two objects, k is a constant, and r is the distance between the two objects. Derive an expression for the force as a function of the distance r, F(r). From your result, determine a) Which direction does the force act if the two objects have oppositely signed charges b) Which direction does the force act if the two objects have charges with the same sign (c) Extra credit: consider how the electrostatic force F(r) accounts for the behavior of the electron in the hydrogen atom as it moves around the nucleus, a proton. Why does it require input of energy to detach an electron from a hydrogen atom by making it move away from the proton?

Explanation / Answer

Electrostatic force = V(r) / r = k q1 q2/ r2

Direction of Force(F)

* For similar charges( Repulsion) : away from each other

*For opposite charges( attraction): towards each other

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