Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

The following questions (13 and 14) refer to the equilibrium shown here: 4NH3(g)

ID: 1081118 • Letter: T

Question

The following questions (13 and 14) refer to the equilibrium shown here: 4NH3(g) + 502(g) 4NO(g) 6H20(g) 12. What would happen to the system if oxygen were added? Explain. a) More ammonia would be produced. b) More oxygen would be produced. c) The equilibrium would shift to the right. d) The equilibrium would shift to the left. e) Nothing would happen 13. What would happen to the system if the pressure were decreased? Explain. Nothing would happen b) a) c) d) e) More oxygen would be produced. The water vapor would become liquid water. The ammonia concentration would increase. The NO concentration would increase. 14. For a certain reaction at 25.0°C, the value of K is 1.2 × 10 At 50.0°C the value of K is 3.4 x 101. This means that the reaction is a) exothermic b) endothermic c) never favorable d) more information needed e) none of these (a-d)

Explanation / Answer

consider the given reaction

4 NH3 + 5 O2 <--> 4 NO + 6 H2O

12) given that O2 is added to system

now

according to Le Chatlier principle

the equilibrium will shift in a direction to counter the change

since O2 is added , the equilibrium will try to get rid of O2

so

O2 will be used up to from products

so the answer should be

c) the equilibrium would shift to the right


13) in this case , pressure is decreased

so according to Le Chatlier principle

the equilibrium will try to increase the pressure

we know that

more the gases , more will the pressure

so

to increase the pressure , the equilibrium will shift to the side where there are more moles of gases

so the equilibrium will shift towards the products side

the answer is

e) The NO concentration would increase

14)

we know that

ln(k2/k1) = (dH/R) (1/T1 - 1/T2)

given

T1 = 298 kelvin and k1 = 0.0012

T2 = 323 kevin and k2 = 0.34

we see that

k2 > k1 , pluging those values in the above equation

we get

dH > 0

so the reacion will be endothermic

b) endothermic