need to find the values for the blanks. I\'m confused about the calculations tho

Question

need to find the values for the blanks.
I'm confused about the calculations though. if someone can help by showing the calculations and steps that would be absolutely amazing and help me greatly!

Data Table: Concentration of CaCl2 Concentration of Nato, lemes Trial #1 Trial #2 Trial #3 Trial #4 Volume, Caci 24.32 242 22.3 Volume Naco, 24 5. L 10.2 Moles of CaCl Moles of Na CO Limiting Reactant Mass of Filter paper Filter paper + Solid- 31 2 320 1·! Actual Yield Theoretical Yield Percent Yield Moles Ca2 excess Moles CO2 excess

Explanation / Answer

Trial #1
Moles of CaCl2 = 0.5 mol/L * (24.3/1000)L = 0.01215 mol
Moles of Na2CO3 = 1 mol/L * (24.1/1000)L = 0.0241 mol
Limiting reactant - CaCl2
Actual yield = 1.655 - 0.320 = 1.335 gm
Na2CO3 (aq) + CaCl2 (aq) -------> CaCO3 (s) + 2 NaCl (aq)
1 mol of CaCl2 gives 1 mol of CaCO3
0.01215 mol of CaCl2 gives ? mol of CaCO3
cross multiply to get the answer,
0.01215 mol of CaCO3 are produced
Theoretical yield = 0.01215 mol * 100.0869 g/mol = 1.21605 gms of CaCO3
[ molar mass of CaCO3 = 100.0869g/mol ]
Since actual yield > theoretical yield,
Percent yield = [theoretical yield / actual yield] *100 = [1.21605 / 1.335]*100 = 91.09 ~ 91.1%
Moles Ca+2 excess = Moles CO3-2 excess = 0.0241 - 0.01215 = 0.01195 mol

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