Dilution Problems For problems 7-11 use the dilution equation: Concentration is
ID: 1084993 • Letter: D
Question
Dilution Problems For problems 7-11 use the dilution equation: Concentration is in Moles/ Liter and V is in Liters 6. What is the concentration (molarity) of a solution of NaCl if 40 mL of a 2.5 M NaCI solution is diluted to a total volume of 500 mL? 7. What is the concentration of a solution of Fe(NOs)s if 80 mL of a 3.0 M Fe(NOs)s solution is diluted to a total volume of 1500 mL? 8. What is the concentration of a solution of KOH if 75 mL of a 2.25 M KOH solution is diluted to a total volume of 250 mL? 9. What is the concentration of a solution of CaSOs if 8.0 mL of a 1.0 M CaSOs solution is diluted to a total volume of 100 mL? 10. How many mL of 6.0 M HCI is needed to make 250 mL of a 1.5 M HCI solution 11. How many ml of 12.0 M HCI is needed to make 250 mL of a 1.5 M HCI solution?Explanation / Answer
Using the formula, C1V1 = C2V2
C1 = initial concentration of the compound
V1 = initial volume of the compound
C2 = final concentration of the compound
V2 = final volume of the compound
6.
C1 = 2.5 M
V1 = 40 mL
C2 = ?
V2 = 500 mL
from the formula,
2.5 * 40 = C2 * 500
C2 = 0.2 M is the final concentration of NaOH
7.
C1 = 3 M
V1 = 80 mL
C2 = ?
V2 = 1500 mL
from the formula,
3 * 80 = C2 * 1500
C2 = 0.16 M is the final concentration of Fe(NO3)3.
8.
C1 = 2.25 M
V1 = 75 mL
C2 = ?
V2 = 250 mL
from the formula,
2.25 * 75 = C2 * 250
C2 = 0.675 M is the final concentration of KOH.
9.
C1 = 1 M
V1 = 8 mL
C2 = ?
V2 = 100 mL
from the formula,
1 * 8 = C2 * 100
C2 = 0.08 M is the final concentration of CaSO3.
10.
C1 = 6 M
V1 =
C2 = 1.5 M
V2 = 250 mL
from the formula,
6 * V1 = 1.5 * 250 mL
V1 = 62.5 mL of HCl is required to get the desire dilution.
11.
C1 = 12 M
V1 = ?
C2 = 1.5 M
V2 = 250 mL
from the formula,
12 * V1 = 1.5 * 250 mL
V1 = 31.25 mL of HCl required to get the desire dilution.
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