Determine an unknown volume or concentration using an oxidation–reduction titrat

Question

Determine an unknown volume or concentration using an oxidation–reduction titration. The concentration of a Sn2+ solution is determined by titrating it with a 0.1317 M solution of permanganate. The balanced net ionic equation for the reaction is shown below. 2 MnO4-(aq) + 5 Sn2+(aq)+16 H3O+(aq)2 Mn2+(aq) + 5 Sn4+(aq)+24 H2O(l) In one experiment, 17.93 mL of the 0.1317 M MnO4- solution is required to react completely with 20.00 mL of the Sn2+ solution. Calculate the concentration of the Sn2+ solution

Explanation / Answer

2 MnO4-(aq) + 5 Sn2+(aq)+16 H3O+(aq)   -----------> 2 Mn 2+(aq) + 5 Sn4+(aq) + 24 H2O(l)

moles of MnO4- = 17.93 x 0.1317 / 1000

                           = 2.36 x 10^-3 mol

2 mol MnO4-   -------------->   5 mol Sn+2

2.36 x 10^-3 mol MnO4- -------------> ??

moles of Sn+2 =    2.36 x 10^-3 x 5 / 2

   = 5.90 x 10^-3 mol

moles = molarity x volume

5.90 x 10^-3 = concentration x 0.020

concentration of Sn+2 = 0.2952 M

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