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Question

takeAssignment/take ovalentActivity do?loctor-assignmen ake tak AssonmentSessor locator e o . Use the References to areess impartant valbrs if seeded far this urstion. A student is asked to standardize a solution of potassium hydroxide. He weighs out 0.917 gpotassiuem hydrogen plthalate (KHC H,O4, treat this as a monoprotic acid). t requires 20.5 ml of potassium hydrexide to reach the endpoint A. What is the molarity of the potassim hydreside solution? This potassiunhydr side solution is then used to tinde·uninowe solution ofhydrokewnic acid B. If 17.7 ml. of the potassium hydreside solution is required to neutralize 24.7 mL of hy drebromic acid, what is the molarity of the hydrobromie acid solution? Gubmit Answer Retry Entire Group 8 more group attempts remaining

Explanation / Answer

A)Molarity=no.of moles of solute/volume of solution(in litres)

Number of moles = given weight/molecular wieght)...=0.917/204.2=0.0045

Now,according to the above formula,Molarity =(0.0045*1000)/20.5=0.17M

B)M1V1=M2V2

M1=molarity of potassium hydroxide =0.17M

M2=molarity of hydrochloric acid=x

V1=volume of potassium hydroxide=17.7ml

V2=volume of hydrochloric acid=24.7ml

Now,

Therefore,

0.17*17.7=x*24.7

X=0.13M

Therefore molarity of HCl is 0.13M

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