Calculate K at a certain temperature for the following reaction: PCls(g) = PCl3(

Question

Calculate K at a certain temperature for the following reaction: PCls(g) = PCl3(g) + Cl2(g) If initial the reaction started at 2.3 x 10-2 M PCls and at equilibrium the mixture contains 1.5 x 10-2 M PCl3 and 1.5 x 10-2 M C12.

2. Calculate K at a certain temperature for the following reaction: PCIs(g) PCI3(g) + Cl2(g) If initial the reaction started at 2.3 x 10-2 M PCls and at equilibrium the mixture contains 1.5 x 10-2 M PCl3 and 1.5 x 10-2 M Cl2. What was the purpose of the sulfuric acid in this reaction? Why does it not appear in the K expression? 3.

Explanation / Answer

PCl5(g)---->. PCl3(g) + Cl2(g)

Initial:2.3*10-2 . 0 . 0

Change: -x . +x. +x

Equilbr:2.3*10-2-x . x. x

At equilibrium,

[PCl3] = x = 1.5*10-2M

[Cl2] = x = 1.5*10-2M

[PCl5] = 2.3*10-2M - 1.5*10-2M = 0.8*10-2M

Kc = [PCl3][Cl2] / [PCl5]

= 1.5*10-2M*1.5*10-2M / 0.8*10-2M

Kc = 2.8*10-2

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