data table; this data table vwill be The following table can be used as a guide

Question

data table; this data table vwill be The following table can be used as a guide to make a MS EXCEL used to create your graph. DYE Rate of the log ERG log(Rate) volume of BLUE blue dye concentration reaction Group Average time At average (sec) used use for the trial (mL) ERG] M 5a 15hL 3,5215 106 0120 4101-5,412-691s6 7a | qb | 10 mL | 5.oar 3-0-610. 1061 x 10-c -5.29251-6.9742 8a 96125ml 6.36916-10 90.092007032 6a Data Analysis 2: Order of reaction for hypochlorite ion. Calculate the rate of the reaction (Note that the volume of Blue Dye these trials trial) will be 10.0 mL for each of Rate = - ERGI At average

Explanation / Answer

A) Convert 5.5% by mass of NaClO to molarity:

% by mass = 5.5%

Mass = 5.5/100 = 0.055g of NaClO

Molecular mass of NaClO = 74.49 g/mol

Number of moles of NaClO = Mass of NaClO/Molecular mass of NaClO = 0.055/74.49 = 0.000738 moles

Density of solution = 1g/cm3

Density = mass/volume

therefore, volume of solution = mass/density = 0.055/1 = 0.055ml

Molarity = no.of moles/volume of solution = 0.000738/0.055 = 0.01342 molar

B) [ ClO-]

[ClO-] = [(Concentration of NaClO in stock x volume of bleach) - (ERG)]/Total volume of solution

Concentration of NaClO in stock = 5.5% = 0.01342 M

ERG = 5.0953 x 10-6

Total volume of solution = 30.0ml

volume of bleach = refer table 2

1. [ClO-] = [(0.01342 x 5 ) - 5.0953 x 10-6] / 30 = 2.24 x 10-3

2. [ClO-] = [(0.01342 x 7.5 ) - 5.0953 x 10-6] / 30 = 3.35 x 10-3

3. [ClO-] = [(0.01342 x 10.0 ) - 5.0953 x 10-6] / 30 = 4.47 x 10-3

4. [ClO-] = [(0.01342 x 12.5 ) - 5.0953 x 10-6] / 30 = 5.59 x 10-3

C) Rate = [ClO-]/ taverage

1. Rate = (2.24 x 10-3) / 172 = 1.30 x 10-5

2. Rate = (3.35 x 10-3) / 103 = 3.25 x 10-5

3. Rate = (4.47 x 10-3) / 81 = 5.52 x 10-5

4. Rate = (5.59 x 10-3) / 96 = 5.82 x 10-5

D) Log [ClO-]

1. log(2.24 x 10-3) = - 2.6498

2. log(3.35 x 10-3) = - 2.4749

3. log(4.47 x 10-3) = - 2.3497

4. log(5.59 x 10-3) = - 2.2526

E) log (rate)

1. log(1.30 x 10-5) = -4.8860

2. log(3.25 x 10-5) = -4.4881

3. log(5.52 x 10-5) = -4.2581

4. log(5.82 x 10-5) = -4.2351

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