Throughout our lectures, we have learned that our body\'s primary defense agains

Question

Throughout our lectures, we have learned that our body's primary defense against high temperatures is through sweating (perspiration). Let's consider a 200 lb (91 kg) male farmer in the Central Valley of California on a July day when the air temperature is 110 degree F (43 degree C). On this day, the humidity is low enough that all the sweat evaporates from the farmer's skin, enabling him to maintain a body temperature of 100 degree F (38 degree C). The farmer sweats l liter (1000 g) per hour and 60% of the latent heat needed to evaporate this sweat is provided by farmer's body (the other 40% is provided by the air). If the farmer suddenly dehydrates and stops sweating, how long will it take for his body temperature to rise to a near-fatal 110 degree F (43 degree C)? Please show all of your. Assumptions you will need to use: 1. It takes 4200 Joules of energy to warm each kilogram (kg)of his body 1 degree C (1.8 degree F). 2. The latent heat of vaporization is 2, 400,000 J/kg. This value means that it takes 2, 400,000 Joules of energy to convert one kilogram of sweat (a liquid) into a gas.

Explanation / Answer

Drought can be defined as the condition of earth periodical processes which arise due to the fact that when there is a shortage of water in a perticular region than there will be shortage of water and hence loss in the groun water table.

In the above problem the farmer is sweating due to dryness and summer and hence there will be loss of water from his body in the form of sweat and heat. the calorie he burn will be equal to the burn fat through which he sweating. it can be taken in the form of heat radiation from body.

so the energy required to rased his body temperature from 38 to 43 having 5 degree increament

and each increament possible to raised by 4200 joule of energy

so the total energy required is 4200x5=21000 joule.

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