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The product development group of a high-tech electronics company developed five

ID: 1138306 • Letter: T

Question

The product development group of a high-tech electronics company developed five proposals for new products. The company wants to expand its product offerings, so it will undertake all projects that are economically attractive at the company’s MARR of 20% per year. The cash flows (in $1000 units) associated with each project are estimated. Which projects, if any, should the company accept on the basis of a present worth analysis?

Project

A

B

C

D

E

Initial Investment

$-700

$-1,300

$-500

$-1,500

$-1,200

Operating Cost, per Year

$-150

$-200

$-250

$-300

$-400

Revenue, per Year

$300

$225

$550

$600

$750

Salvage Value

$10

$30

$5

$20

$120

Life

3 years

10 years

5 years

8 years

4 years

The present worth of project each A,B,C,D,E are:

Project

A

B

C

D

E

Initial Investment

$-700

$-1,300

$-500

$-1,500

$-1,200

Operating Cost, per Year

$-150

$-200

$-250

$-300

$-400

Revenue, per Year

$300

$225

$550

$600

$750

Salvage Value

$10

$30

$5

$20

$120

Life

3 years

10 years

5 years

8 years

4 years

Explanation / Answer

PW of A=PW of Cash Outflow-PW of Cash Inflow

Cash Outflow=Operating Cost, Initial Investment

Cash Inflow=Revenue, Salvage

PW of A=300/1.1+300/1.1^2+300/1.1^3+10/1.1^3-150/1.1^1-150/1.1^2-150/1.1^3-700=-$319.46K

PW of B=225(1/1.1+...1/1.1^10)+30/1.1^10-200(1/1.1+...1/1.1^10)-1300=225*6.114+11.56-200*6.114-1300=-$1135.6K

PW for C=550(1/1.1+...1/1.1^5)+5/1.1^5-250(1/1.1+...1/1.1^5)-500=550*3.8+3.10-250*3.8-500=643.1K

PW for D=600(1/1.1+...1/1.1^8)+20/1.1^5-300(1/1.1+...1/1.1^8)-1500=600*5.33+9.33-300*5.33-1500=108.33K

PW for E=750(1/1.1+...1/1.1^4)+120/1.1^5-400(1/1.1+...1/1.1^8)-1200=750*3.17+81.96-400*3.17-1200=-8.54K