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QUESTION 1 You are buying a new car and can pay $15,000 cash today or pay $350 p

ID: 1169486 • Letter: Q

Question

QUESTION 1

You are buying a new car and can pay $15,000 cash today or pay $350 per month for 60 months. If the annual interest rate is 12%, which alternative has the lower PWc?

both have the same PWc

cannot be determined from the information given.

$15,000 today

$350 per month for 60 months

QUESTION 2

You can buy a new sorting machine for $15,000. Annual operation and maintenance will cost $6000 which is $8000 less than current costs. You expect to sell the machine for $2000 at the end of 10 years. If i= 8%:

PWc = $15,000

PWc = $15,000 + 6000(P/A,8%,10) - 2000(P/A,8%,10)

PWc = $15,000 + 6000(P/A,8%,10) + 2000(P/F,8%,10)

PWc = $15,000 + 6000(P/A,8%,10) - 2000(P/F,8%,10)

QUESTION 3

You can buy a new sorting machine for $15,000. Annual operation and maintenance will cost $6000 which is $8000 less than current costs. You expect to sell the machine for $2000 at the end of 10 years. If i= 8%:

PWb = 8000

PWb = 8000(P/A,8%,10)

PWb = 14000

PWb = 14000(P/A,8%,10)

QUESTION 4

You can buy a new sorting machine for $15,000. Annual operation and maintenance will cost $6000 which is $8000 less than current costs. You expect to sell the machine for $2000 at the end of 10 years. Should you buy this machine if i = 8%?

Yes, because NPW > 0

Yes, because NPW < 0

No, because NPW > 0

No, because NPW < 0

QUESTION 5

You consider purchasing a computer system for $12,000. Annual upgrades will cost $500. Your expected salvage value is $1000 at the end of 5 years. The system is faster and will save you $4000 per year over your current system. If the interest rate = 10%:

EUAC = 12000 + 500(P/A,10%,5) - 1000(P/F,10%,5)

EUAC = 12000(A/P,10%,5) + 500 - 1000(A/F,10%,5)

EUAC = 12000(A/P,10%,5) - 500 - 1000(A/F,10%,5)

EUAC = 12000(A/P,10%,5) - 500 + 1000(A/F,10%,5)

QUESTION 6

You consider purchasing a computer system for $12,000. Annual upgrades will cost $500. Your expected salvage value is $1000 at the end of 5 years. The system is faster and will save you $4000 per year over your current system. If the interest rate = 10%:

EUAC = $1562

EUAC = $2802

EUAC = $3502

EUAC = $3719

QUESTION 7

You consider purchasing a computer system for $12,000. Annual upgrades will cost $500. Your expected salvage value is $1000 at the end of 5 years. The system is faster and will save you $4000 per year over your current system. If the interest rate = 10%:

EUAB = $500

EUAB = $1000

EUAB = $2400

EUAB = $4000

QUESTION 8

You consider purchasing a computer system for $12,000. Annual upgrades will cost $500. Your expected salvage value is $1000 at the end of 5 years. The system is faster and will save you $4000 per year over your current system. If the interest rate = 10%, should you purchase the computer system?

Yes, because B/C > 1

Yes, because B/C < 1

No, because B/C > 1

No, because B/C < 1

QUESTION 9

A successful alumna donates $500,000 to the OIT scholarship fund. If i = 6%, how much money can be given to worthy students each year without reducing the $500,000 principal?

$8333

$15,000

$30,000

$50,000

QUESTION 10

A successful OIT graduate wants to set up an endowment that will pay $50,000 per year forever for maintenance of her favorite m,ountain bike trail. If the interest rate is 5%, how much must she set aside today to fund this endowment?

$25,000

$50,000

$500,000

$1,000,000

QUESTION 11

You earn $65,000 in 2012. What will your salary be at the end of 2017 if your salary increases by 6% per year?

$68,900

$73,604

$86,985

$87,106

QUESTION 12

If you spend $5,000 on gasoline this year and prices increase 20% per year for the next three years, how much will you pay 3 years from now assuming you keep the same vehicle and drive the same number of miles?

$5,306

$8,640

$12,539

$14,633

a.

both have the same PWc

b.

cannot be determined from the information given.

c.

$15,000 today

d.

$350 per month for 60 months

Explanation / Answer

Answers with brief description are given below.

Answer 1 is (b)
Reason: the PWc of the other alternative is $350(P/A, 1%, 60) = 350(44.955) = 15,734.25

Answer 2 is (d)
Reason: the present value of salvage value is deducted from, not added to, the PWc.

Answer 3 is (d)
Reason: Total savings every year is $14,000. The present value of that is 14000(P/A, 8%, 10)

Answer 4 is (a)
Reason: PWb - Pwc > 0

Answer 5 is (b)
Reason: The equivalent uniform annual value of the salvage value is deducted from the equivalent uniform annual value of the expenses associated with the machine

Answer 6 is (c)
Reason: 12000(0.2638)+500-1000(0.1638) = 3502.

Answer 7 is (d)
Reason: total savings every year from the new system is $4000

Answer 8 is (a)
Reason: $4000/$3502 > 1

Answer 9 is (c)
Reason: 500000(0.06) = (c)

Answer 10 is (d)
Reason: 50000/0.05 = (d)

Answer 11 is (c)
Reason: 65000(1+0.06)5= (c)

Answer 12 is (b)
Reason: 5000(1+0.20)3=(b)

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