2). Given the hypothetical basin in the diagram and the other information below,
ID: 117602 • Letter: 2
Question
2). Given the hypothetical basin in the diagram and the other information below, list the sources of water flowing into and out of the basin and calculate a water balance. 12 inches= 1 ft 640 acres1 square mile 5280 ft= 1 mile Basin area= 100 square miles Vegetated area-90 square miles Reservoir area = 10 square miles Change in reservoir level =-2 ft Evapotranspiration rate- 12 inches per year Precipitation -36 inches per year m flow from mountains measured by gauge stations 20 Canal flow = 40,000 acre-ft/year Evaporation rate from reservoir- 48 inches per year River flow from river stage measurements- 50,000 acre-ft/yr : CANEExplanation / Answer
note :
1 acre feet = 0.0000002959 cubic mile
1feet = 0.00019 mile
Given,
basin area = 100sq miles
vegetated area = 90 sqmiles
reservoir area = 10 sqmiles
change in reservoir level = -2ft = 2 * 0.00019 mile = 0.00038miles
evapotranspiration rate = 12 inches per year = 1ft /year = 0.00019 mile/year
precipitation = 36 inches per year = 3 ft/year = 3*0.00019 mile/year = 0.00057 mile/year
stream flow from mountains measured by guage stations = 20000 acre-feet/year = 20000*0.0000002959 cubic mile/year = 0.005918 cubic mile/year
canal flow = 40000 acre-feet/year = 40000*0.0000002959 cubic mile/year = 0.0011836 cubic mile /year
evaporation rate from reservoir = 48 inches per year = 4 ft/year = 4 * 0.00019 mile/year = 0.00076 mile/year
river flow from stage measurements = 50000 acre-feet/year = 50000 *0.0000002959 cubicmile/year = 0.014795 cubic mile/year
water balance equation = inflow - storage change = outflow
(precipitation + stream flow from mountains) - ( evapotranspiration + canal flow + evaporation rate from reservoir + river flow from stage measurements ) = change in reservoir level
(0.00057 mile/year *100sqmiles ) + (0.005918 cubic mile) - {( 0.00019 mile/year * 90 sqmiles ) + 0.0011836 + (0.00076 mile/year * 10 sqmiles ) + 0.014795 cubic mile/year
= storage change = 0.00038 miles * 10 sqmiles = 0.0038 cubic miles
hence inflow = 0.05
outflow = 0.05 nearly
hence water balance proved
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