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To perform a test of the null and alternative hypotheses shown below, random sam

ID: 1210962 • Letter: T

Question

To perform a test of the null and alternative hypotheses shown below, random samples were selected from the two normally distributed populations with equal variances. The data are shown below. Test the null hypothesis using an alpha level equal to 0.10.

Sample from Population 1: 33,43,27,36,37,34,26,39,42,39

Sample from Population 2: 45,53,37,47,41,38,41,47,48,43

H0: 1 2 = 0

HA: 1 – 0

Determine the rejection region for the test statistic t. Select the correct choice below and fill in the answer box(es) to complete your choice.

A. t < ____ or t > ____

B. t > ___

C. t < ___

Calculate the value of the test statistic. t = ___

Since the test statistic ____ (is not, or is) in the rejection region, _____ (reject, or do not reject) the null hypothesis. There is ____ (sufficient, or insufficient) evidence to conclude that the two population means are different.

Explanation / Answer

First step is to represent our scientific question is the null and alternative

hypothesis.

The null: Ho: m1-m2 = 0 represents the condition that the populations are centered

in the same spot.

As with one-sample and matched pairs hypothesis testing we can have a one-sided

or two-sided alternative.

The two sided alternative is that the means differ. That is m1-m2 does not equal

zero.

It is two sample problem with 1 and 2 not equal

So we use t test for the same

So for that we have to find out Xbar and S for both data

X1 bar = 35.6 X2 bar = 44

And s1= 5.74 and s2 = 4.94

T= -6.926

Paired Samples Statistics

Mean

N

Std. Deviation

Std. Error Mean

Pair 1

one

35.60

10

5.739

1.815

two

44.00

10

4.944

1.563

Paired Samples Test

Paired Differences

Mean

Std. Deviation

Std. Error Mean

95% Confidence Interval of the Difference

Lower

Upper

Pair 1

one - two

-8.400

3.836

1.213

-11.144

-5.656

Paired Samples Test

t

df

Sig. (2-tailed)

Pair 1

one - two

-6.926

9

.000

Paired Samples Statistics

Mean

N

Std. Deviation

Std. Error Mean

Pair 1

one

35.60

10

5.739

1.815

two

44.00

10

4.944

1.563

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