A majorette in a parade is performing some acrobatic twirlings of her baton. Ass

Question

A majorette in a parade is performing some acrobatic twirlings of her baton. Assume that the baton is a uniform rod of mass 0.120kg and length 80.0cm .

A) Initially, the baton is spinning about a line through its center at angular velocity 3.00rad/s . (Figure 1) What is its angular momentum? Answer: 0.0192 kg*m^2/s

B) With a skillful move, the majorette changes the rotation of her baton so that now it is spinning about an axis passing through its end at the same angular velocity 3.00rad/s as before.(Figure 2) What is the new angular momentum of the rod? (Answer in kg*m^2/s)

Just need help with B!

Explanation / Answer

part B :

apply the law of conservation of angular momentum

L1 = L2

I1 W1 = I2 W2

here Moment of Inertia of thin rod at one end is ML^2/3

I = 0.120 * 0.8*0.8/3

I = 0.0256 Kgm^2

so Angular L2 = I2 W2

L2 = 0.0256 * 3

L2 = 0.0768 Kgm^2/s------------<<<<<<<<<<<Answer

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