A majorette in a parade is performing some acrobatic twirlings of her baton. Ass

Question

A majorette in a parade is performing some acrobatic twirlings of her baton. Assume that the baton is a uniform rod of mass 0.120kg and length 80.0cm.

A) Initially, the baton is spinning about a line through its center at angular velocity 3.00rad/s . (Figure 1) What is its angular momentum? Answer: 0.0192 kg*m^2/s

B) With a skillful move, the majorette changes the rotation of her baton so that now it is spinning about an axis passing through its end at the same angular velocity 3.00rad/s as before. What is the new angular momentum of the rod? (Express in kilogram meters squared per second)

Just need help with B!

Explanation / Answer

B)

Here , I = 1/3 * ml^2

I = 0.12 * 0.80^2/3

I = 0.0256 Kg.m^2

Now , angular momentum = I*w

angular momentum = 0.0256 * 3

angular momentum = 0.0768 Kg .m^2/s

the angular momentum is 0.0768 Kg .m^2/s

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