A proton with a speed of 2.20?10 6 m/s is shot into a region between two plates

Question

A proton with a speed of 2.20?106m/s is shot into a region between two plates that are separated by a distance of 0.195 m. As the drawing shows, a magnetic field exists between the plates, and it is perpendicular to the velocity of the proton. What must be the magnitude of the magnetic field (in T), so the proton just misses colliding with the opposite plate?

Please show all work and explain your methods

A proton with a speed of 2.20?106m/s is shot into a region between two plates that are separated by a distance of 0.195 m. As the drawing shows, a magnetic field exists between the plates, and it is perpendicular to the velocity of the proton. What must be the magnitude of the magnetic field (in T), so the proton just misses colliding with the opposite plate? Please show all work and explain your methods

Explanation / Answer

Here , for missing out colliding with other plate ,

radius of trjectory , r = 0.195 m

Now . r = mv/Bq

0.195 = mp*2.2 *10^6 / (B * e)

solving for B

B = 0.118 T

the required magnetic field is 0.118 T

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.