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eans- PHYS 1061 Spring15. Stokes Activities and Due Dates Hw 6: Work and Kinetic

ID: 1260642 • Letter: E

Question

eans- PHYS 1061 Spring15. Stokes Activities and Due Dates Hw 6: Work and Kinetic Energy Gradebook (3 3/18/2015 11:55 PM 6 84.5loo 3/17/2015 11:07 AM Print Icalaualor Question 15 of 17 the figure below are three vectors. Vector A has a length of 380, B's length is 61.0, and cis 23.0. Find the following A. B 3810 B. M C- 6120 Ewhat angles above and below the horizontal inboud vector Abe at so that A B-o? O 20 above, or 160 below O 90° above, or 70 below O 90" above, or 90" below O 110 above, or 70 below o Previous ® Gve up s wew souson checks Answer O Next HExt about us careers partners privacy policy terms of use contact MacBook Air

Explanation / Answer

PART A:

A dot B = A B cos (T)

Here, T = 50 degrees = angle between A and B. Thus,

A dot B = 38.0 * 61.0 * cos 50 = 1490 [ANSWER, PART A]


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PART B:

Summing A and C's components:

Ax = Acos70 = 12.997
Ay = Asin70 = 35.708

Bx = Bcos20 = 57.321
By = Bsin20 = 20.863

Cx = Ccos(-70) = 7.866
Cy = Csin(-70) = -21.613


Thus,

A + C = <20.863, 14.095>

Thus,

B dot (A + C) = 1490   [ANSWER, PART B]

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A dot B = 0

If A is perpendicular to B. Thus, that happens when

110 above, 70 below   [OPTION D, ANSWER]