Compute the equivalent resistance of the network in the figure below, and find t

Question

Compute the equivalent resistance of the network in the figure below, and find the current in each resistor. (R1 = 2.00 ?, R2 = 5.00 ?, R3 = 15.0 ?, R4 = 7.00 ?, and ? = 57.0 V.) The battery has negligible internal resistance.
equivalent resistance
?
current in each resistor
A (Resistor R1)
A (Resistor R2)
A (Resistor R3)
A (Resistor R4)

Compute the equivalent resistance of the network in the figure below, and find the current in each resistor. (R1 = 2.00 ?, R2 = 5.00 ?, R3 = 15.0 ?, R4 = 7.00 ?, and ? = 57.0 V.) The battery has negligible internal resistance. equivalent resistance ? current in each resistor A (Resistor R1) A (Resistor R2) A (Resistor R3) A (Resistor R4)

Explanation / Answer

R1,R2 are connected in parllel

then resistance becomes

=2*5/7

=1.428ohms

R3,R4 are connected in parllel

=15*7/22

=4.77ohms

1.428 and 4.77 are connected in series

=1.428+4.77

EQUIVALENT RESISTANCE

=6.198ohms

current flowing through circuit

=57/6.198

=9.196A

in order to determine current through each resistor

kirchoffs law

V1=4.77*9.196

=43.86volts

V2=1.428*9.196

=13.13volts

I1=13.13/2 =6.56A

I2=13.13/5 =2.626A

I3=43.86/15 =2.924A

I4=43.86/7 =6.265A

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.