The figure below shows a long straight wire just touching a loop carrying a curr
ID: 1261230 • Letter: T
Question
The figure below shows a long straight wire just touching a loop carrying a current I1. Both lie in the same plane.
Q:What direction must the current I2 in the straight wire have to create a field at the center of the loop in the direction opposite to that created by the loop?
Use the compass rose to specify the direction. 2 options
NE to SW or SW to NE
Q:What is the ratio of I1/I2 that gives zero field strength at the center of the loop?
Q:What is the direction of the field directly above the loop under this circumstance?
Field above loop
Explanation / Answer
apply Hall Voltage V = Ed
where E is Electric field = BVd
and Vd is Drift spped = i/neA
so Hall Voltgae Vh = B* (i/neA) * d
n = iBd/(Vh e L)
n = 3 * (6.5) * 1e-3/(1.2 e-6 * 1.6 e-19 )
n = 1.015 e23 no. of electrons /m^3
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