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The figure below shows a small disk of radius r = 2.00 cm has been glued to the

ID: 1261598 • Letter: T

Question

The figure below shows a small disk of radius r = 2.00 cm has been glued to the edge of a larger disk of radius R = 4.00 cm so that the disks lie in the same plane. The disks can be rotated around a perpendicular axis through point O at the center of the larger disk. The disks both have a uniform density (mass per unit volume) of 1.40

The figure below shows a small disk of radius r = 2.00 cm has been glued to the edge of a larger disk of radius R = 4.00 cm so that the disks lie in the same plane. The disks can be rotated around a perpendicular axis through point O at the center of the larger disk. The disks both have a uniform density (mass per unit volume) of 1.40 x 10^3kg/m^3 and a uniform thickness of 0.003 m. What is the rotational inertia of the two-disk assembly about the rotation axis through O.

Explanation / Answer

By Theorem of Parallel axis we have

Io=I+m*d^2 where d is the distance of origin of smaller circle from the larger circle

Mass of larger circle=1.4*10^3*pi*(4*10^-2)^2*0.003

=0.0211 kg

Mass of smaller circle=1.4*10^3*pi*(2*10^-2)^2*0.003

=5.27*10^-3 Kg

Net Moment of Inertia

Io=M1*R^2+M2*r^2+M2*d^2

=5.48*10^-5 Kg-m^2 ans

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