An object is located 14.5 cm in front of a convex mirror, the image being 6.95 c
ID: 1262737 • Letter: A
Question
An object is located 14.5 cm in front of a convex mirror, the image being 6.95 cm behind the mirror. A second object, twice as tall as the first one, is placed in front of the mirror, but at a different location. The image of this second object has the same height as the other image. How far in front of the mirror is the second object located? An object is located 14.5 cm in front of a convex mirror, the image being 6.95 cm behind the mirror. A second object, twice as tall as the first one, is placed in front of the mirror, but at a different location. The image of this second object has the same height as the other image. How far in front of the mirror is the second object located?Explanation / Answer
u = 14.5 cm v = -7 cm 1/ f = 1/v + 1/u f = -13.53 cm M = -v/u = 0.483 Let the object height be ho...the hi = 0.483 *ho The height of second object is, Hi = 0.483 * ho height of 2nd object, Ho = = 2*ho.... Now, -V/U = Hi / Ho = 0.241 1 + v / u = v / f 1 - 0.241 = v / -13.533 v = -10.27 cm so, u = - v / 0.241 = 42.62 cm
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