The 2.0-m-long, 15kg beam in (Figure 1) is hinged at its left end. It is \"falli
ID: 1263012 • Letter: T
Question
The 2.0-m-long, 15kg beam in (Figure 1) is hinged at its left end. It is "falling" (rotating clockwise, under the influence of gravity), and the figure shows its position at three different times.
What is the gravitational torque on the beam about an axis through the hinged end when the beam is at the upper position?
What is the gravitational torque on the beam about an axis through the hinged end when the beam is at the middle position?
What is the gravitational torque on the beam about an axis through the hinged end when the beam is at the lower position?
The 2.0-m-long, 15kg beam in (Figure 1) is hinged at its left end. It is falling (rotating clockwise, under the influence of gravity), and the figure shows its position at three different times. What is the gravitational torque on the beam about an axis through the hinged end when the beam is at the upper position? What is the gravitational torque on the beam about an axis through the hinged end when the beam is at the middle position? What is the gravitational torque on the beam about an axis through the hinged end when the beam is at the lower position?Explanation / Answer
A) torque = mgl/2 cos 20deg = 141 N-m
B) Torque = mgl/2 = 150 N-m
C) Torque = mgl/2 cos 45 deg = 106.1 N-m
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