Not yet fully answered. Need to show all work! Separation distance between diato

Question

Not yet fully answered. Need to show all work! Separation distance between diatomic hydrogen atoms where energy is minimum, then when energy dissociates the H2. Please show all work so I can learn and understand where the values are coming from. Thanks. The potential energy of a diatomic molecule is given by the relation where A and B are constants and r is the separation distance between the atoms. For H2: A = 0.124 x 10^-120 eVm^12 and B = 1.488 x 10^-60 eVm^6. Find the separation distance ro where the energy is minimum and the dissociation energy of H2.

Explanation / Answer

given

U(r) = A/(r)^12 - B/(r)^6

for energy to be minimum

d(U(r))/d(r) = 0

therefore

-12*A/r^13 +6 *B/r^7 =0

2*A/r^6 = B

r^6 = 2*A/B = 2*(0.124*10^(-120))/(1.488 *10^(-60)) = 0.16666666666 * 10^-60

r = 7.4183638e-11 m

dissociation energy is

by substituting r

U(r) = 4.464 - 8.639 = -4.175 ev

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.