Three point charges have equal magnitudes, two being positive and one negative.

Question

Three point charges have equal magnitudes, two being positive and one negative. These charges are fixed to the corners of an equilateral triangle, as the drawing shows. The magnitude of each of the charges is 3uC and the lengths of the sides of the triangle are 2cm. Calculate the magnitude of the net force on the charge C.

Three point charges have equal magnitudes, two being positive and one negative. These charges are fixed to the corners of an equilateral triangle, as the drawing shows. The magnitude of each of the charges is 3uC and the lengths of the sides of the triangle are 2cm. Calculate the magnitude of the net force on the charge C. each of the charges is 3uC and the len ulate the magnitude of the net force separated by a dis

Explanation / Answer

Here ,

as the magnitude of charges and distance is same

the force betweent charges is same in magnitude

F = kq^2/d^2

F = 9*10^9 * (3 *10^-6)^2 /0.02^2

F = 202.5 N

Now , as the FAC and FBC have angle 120 degree between them

Fnet = 2 * F* cos(120/2)

Fnet = 2 * 202.5 * cos(60)

Fnet = 202.5 N

magnitude of net force acting on C is 202.5 N

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