A particle of charge 22 A particle of charge 22 MuC and mass 1.2 multiply.gif 10

Question

A particle of charge 22

A particle of charge 22 MuC and mass 1.2 multiply.gif 10-15 kg moves at a speed of 1925 m/s, and its velocity vector lies in the x-y plane. There is a magnetic field of magnitude 0.82 T along the +z direction. The magnetic force on the particle causes the particle to move in a circle that lies in the x-yplane. (a) Find the radius of this circle. ? m (b) Find the period of the motion. ? s (c) If the particle is moving parallel to +y at t = 0, is the circular motion clockwise or is it counterclockwise as viewed from along the +zaxis? (choose one) clockwise or counterclockwise

Explanation / Answer

Given,

magnetic field = 0.82 T

speed of the particle = 1925 m/s

mass of the particle = 1.2 * 10^-15 kg

charge of the particle = 22 * 10^-6 C

radius = mass * velocity / charge * magnetic field

radius = 1.2 * 10^-15 * 1925 / 22 * 10^-6 * 0.82

radius = 1.28 * 10^-7 m

period of motion = 2 * pi * r / v

period of motion = 2 * pi * 1.28 * 10^-7 / 1925

period of motion = 4.177 * 10^-10 sec

If the particle is moving parallel to +y at t = 0, is the circular motion clockwise as viewed from along the +zaxis

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