A particle of charge 25 A particle of charge 25 mu C and mass 1.6 Times 10-15 kg

Question

A particle of charge 25

A particle of charge 25 mu C and mass 1.6 Times 10-15 kg moves at a speed of 1830 m/s, and its velocity vector lies in the x-y plane. There is a magnetic field of magnitude 0.91 T along the +z direction. The magnetic force on the particle causes the particle to move in a circle that lies in the x-y plane. Find the radius of this circle. Find the period of the motion. If the particle is moving parallel to +y at t = 0, is the circular motion clockwise or is it counterclockwise as viewed from along the +z axis?

Explanation / Answer

a)

r=mV/qB =(1.6*10^-15)*1830/(25*10^-6)(0.91)

r=1.29*10^-7 m

b)

T =2pir/V =2pi*1.29*10^-7/1830

T=4.42*10^-10 s

c)

clockwise

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.