(hrw8c10p54) A cylinder having a mass of 7.0 kg can rotate about its central axi
ID: 1264200 • Letter: #
Question
(hrw8c10p54) A cylinder having a mass of 7.0 kg can rotate about its central axis through point O. Forces are applied as in the figure: F1 = 8.5 N, F2 = 3.5 N, F3 = 1.5 N, and F4 = 6.5 N. Also, R1 = 5.5 cm and R2 = 15.0 cm. Find the magnitude and direction of the angular acceleration of the cylinder.(Take clockwise to be +) (During the rotation, the forces maintain their same angles relative to the cylinder.)
Explanation / Answer
Given that mass of the cyllinder is m = 7.0 kg
??_net = I ?
moment of inertia I = 1/2 M R_2^2
= 1/2 * 7.0 kg * ( 0.15 m)^2
= 0.07875 kg m^2
? ? = F_1 R_2 - F_2 R_2 -F_3 R_1 * F_4 * 0
= 8.5 N * 0.15 m - 3.5 N * 0.15 m - 1.5N * 0.055 m
= 0.6675 N m
angular acceleration ? = ? ? / I
= 0.6675 N m / 0.07875 kg m^2
= 8.476 rad /s^2
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