(hrw8c10p54) A cylinder having a mass of 10.0 kg can rotate about its central ax
ID: 1374538 • Letter: #
Question
(hrw8c10p54) A cylinder having a mass of 10.0 kg can rotate about its central axis through point O. Forces are applied as in the figure: F1 = 10.0 N, F2 = 5.0 N, F3 = 1.5 N, and F4 = 6.5 N. Also, R1 = 5.5 cm and R2 = 13.0 cm. Find the magnitude and direction of the angular acceleration of the cylinder.(Take clockwise to be +) (During the rotation, the forces maintain their same angles relative to the cylinder.)
Explanation / Answer
cosidering clockwise Moments as -ve and anti clock wise moemnts as +ve
we have
(F1-F2)R2 - F3 * R1 + F4 *0 = Toprque
so T = (10-5)* 0.13 - (1.5 * 0.055) + (6.5) *0
T = 4.86 Nm
now use TOrque T = I Alpha
where I = moment of Inertia = mR^2/2
so
Ang Acccleration A = T/I
A = 2T/mR^2
A = 2* 4.86/(10 * 0.13*0.13)
A = 57.51 rad/s^2
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.