(a) What is the net force exerted by the two 3.00- ? C charges on the charge q ?

Question

(a) What is the net force exerted by the two 3.00-?C charges on the charge q?
N

(b) What is the electric field at the origin due to the two 3.00-?C particles?
N/C

(c) What is the electrical potential at the origin due to the two 3.00-?C particles?
kV

Given two particles with Q = 3.00-?C charges as shown in the figure below and a particle with charge q = 1.31 x 10^-18 C at the origin. (Note: Assume a reference level of potential V= 0 at r = ?.) (a) What is the net force exerted by the two 3.00-?C charges on the charge q? (b) What is the electric field at the origin due to the two 3.00-?C particles? (c) What is the electrical potential at the origin due to the two 3.00-?C particles?

Explanation / Answer

Part A and B are both equal to zero because the two are vector quantities, and because both have equal charges the cancel each other out.

Part C can be found using the equation for electric potential which is:

V = ke * q/r

ke = 8.988*10^9 N*m^2/C^2

q = 3.0 *10^-6 C

r = 0.8 m

plug in and solve for V, which turns out to be 33675 V

since there are two charges just multiply V by 2 to get the total eletric potential at the point.

2*V = 67350 V = 67.35 kV

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