(a) What is the net force exerted by the two 3.00- ? C charges on the charge q ?

Question

(a) What is the net force exerted by the two 3.00-?C charges on the charge q?
N

(b) What is the electric field at the origin due to the two 3.00-?C particles?
N/C

(c) What is the electrical potential at the origin due to the two 3.00-?C particles?
kV

Given two particles with Q = 3.00-?C charges as shown in the figure below and a particle with charge q = 1.31 x 10^-18 C at the origin. (Note: Assume a reference level of potential V= 0 at r = ?.) (a) What is the net force exerted by the two 3.00-?C charges on the charge q? (b) What is the electric field at the origin due to the two 3.00-?C particles? (c) What is the electrical potential at the origin due to the two 3.00-?C particles?

Explanation / Answer

a) By symmetry the force due to the left Q towards the right of q is equal to the force due to the right Q towards the left of q, so they cancel out. The net electric force is zero.

b) Electric field is equal but opposite in direction fr the both Q chrages, hence net electric field is also zero.

c) the electric potential due to two charges is

V= 2 k Q/ r = 2 (8.99x10^9)(3x10^-6)/(0.8) = 67425 V or 65.4 kV

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