Two charges are set in place as shown in the diagram. The lower particle has a c

Question

Two charges are set in place as shown in the diagram. The lower particle has a charge of q1 = +2 x 10-9 C. The upper particle has a charge of q2= -3 x 10-9 C.

a) Calculate the Electric Field at Point P.

b) What would be the force on an electron placed at point P?

Two charges are set in place as shown in the diagram. The lower particle has a charge of q1 = +2 x 10-9 C. The upper particle has a charge of q2= -3 x 10-9 C. a) Calculate the Electric Field at Point P. b) What would be the force on an electron placed at point P?

Explanation / Answer

Note that

E = kq / r^2

where r = the distance from the source charge.

Thus, the field due to q1 is

E1 = 2596 N/C

with components

E1x = 2542.755 N/C
E1y = 2542.755 N/C

For q2, it is purely along x,

E2x = -10788 N/C
E2y = 0

Adding these two electric fields by components,

Enetx = -8245.2 N/C
Enety = 2542.755 N/C

Thus,

|Enet| = 8628 N/C   [ANSWER, PART A]

**************************

As

Fnet = q Enet

and q = 1.602E-19 C for an electron,

Fnet = 1.38*10^-15 N   [ANSWER, PART B]

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