1. a) If resistor R1 is 75 and R2 is 2 00 what is the series re sistance (as sho
ID: 1266271 • Letter: 1
Question
1.
a)
If resistor R1 is
75
and R2 is
2
00
what is the series re
sistance
(as shown in
Figure
6
and
Figure
7
)
?
b) If
the power supply is set at 6 volts, what are the voltage and current measured by the sensors in
the series resistance set
-
up of
Figure
7
?
c
) What is the voltage across R1
? (Hint V=IR)
d
) What is the voltage across R2?
e) What is the sum of the voltages across R1 and R2?
f)
What is the current into R1
(as measured by current sensor 1 in
Figure
8
and
Figure
9
)
?
g) What is the current into R2?
2. a) If resistor R1 is
75
and R2 is
2
00
what is the parallel resistance?
b) If
the power supply is set at 6 volts, what are the voltage and current measured by the sensors in
the parallel r
esistance set
-
up of
Figure
10
and
Figure
11
?
c
)
What is the voltage across R2 (as shown in
Figure
12
and
Figure
13
)
?
d)
What is the voltage across R1
?
e)
What is the current into R1
(as measured by current sensor 1 in
Figure
12
and
Figure
13
)
? (Hint
V=IR)
f) What is the current into R2?
g) What is the sum of the currents?
Explanation / Answer
1a)series resistance = R1 + R2 = 75 + 200 = 275 ohm
for V = 6 V;
b)Voltage across series resistance = 6 V
and current = I = V/R = 6/275 = 0.0218 A
c)Voltage across R1 = I*R1 = 0.022 * 75 = 1.635 V
d) Voltage across R2 = I*R2 = 4.36 V
e) sum of voltage across R1 and R2 = 1.635 + 4.36 = 5.995 V
f)current through R1 and R2 is same = I = 0.0218 A
g) current throught R2 = I = 0.0218 A
2)a)R1 and R2 parallel ressistance = R = R1*R2/(R1+R2) = 54.54 ohm
b) Voltage = 6V
current = V/R = 6/54.54 = 0.11 A
c) Voltage across R2 = 6V
d) voltage across R1 = 6 V
voltage across R1 = R2
e)current across R1 = I1 = R2*I/(R1+R2) = 0.08 A
f) current through R2 = I2 = R1*I/(R1+R2) = 0.03A
g) sum of currents = I1 + I2 = 0.08 + 0.03 = 0.11 A
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.