Three long parallel wires are 3.8 cm from one another. (Looking along them, they

Question

Three long parallel wires are 3.8 cm from one another. (Looking along them, they are at three corners of an equilateral triangle.) The current in each wire is

7.00A , but its direction in wire M is opposite to that in wires N and P (Figure 1) .

1)Determine the magnitude of the magnetic force per unit length on wire M due to the other two.

2)Determine the angle of the magnetic force on wire M due to the other two. (measured counterclockwise from the positive x axis )

3)Determine the magnitude of the magnetic force per unit length on wire N due to the other two.

4)Determine angle of the magnetic force on wire N due to the other two. (measured counterclockwise from the positive x axis )

5)Determine the magnitude of the magnetic force per unit length on wire P due to the other two.

6) Determine the angle of the magnetic force on wire P due to the other two.(measured counterclockwise from the positive x axis )

7)Determine the magnitude of the magnetic field at the midpoint of the line between wire M and wire N.

8)Determine the angle of the magnetic field at the midpoint of the line between wire M and wire N. (measured counterclockwise from the positive x axis )

plz explain your work in detail

thx :)

Explanation / Answer

At A the mag of the other two wires is the same and
F/L =?o*I1*I2/2?L = 2x10^-7.0^2/03.8 = 2.58x10^-6N

So F/L total = 2*2.59x10^-5*cos(30) = 4.47x10^-5N

Direction 90o

AT B Same magnitude as A = 4.47x10^-5T

but direction is 300o

At C Magnitude is the same = 4.47x10^-5N

Direction 240o

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