On a frictionless, horizontal air table, puck A (with mass 0.240kg ) is moving t

Question

On a frictionless, horizontal air table, puck A (with mass 0.240kg ) is moving toward puck B (with mass 0.350kg ), that is initially at rest. After the collision, puck A has a velocity of 0.114m/s to the left, and puck B has velocity 0.660m/s to the right.

Part A

What was the speed of puck A before the collision?

Part B

Calculate the change in the total kinetic energy of the system that occurs during the collision.Part B Calculate the change in the total kinetic energy of the system that occurs during the collision.

Explanation / Answer

Part A)

By conservation of momentum

mv = mv + mv

.24(v) = (.24)(-.114) + (.35)(.66)

v = .849 m/s to the right

Part B)

Initial KE = .5(.24)(.849)2 = .0864 J

Final KE = .5(.24)(.114)2 + (.5)(.35)(.66)2 = .0778 J

The difference = .0778 - .0864 = -8.6 X 10-3 J (Negative means it lost KE)

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