On a frictionless, horizontal air table, puck A (with mass 0.150 kg ) is moving

Question

On a frictionless, horizontal air table, puck A (with mass 0.150 kg ) is moving toward puck B (with mass 0.400 kg ), which is initially at rest. After the collision, puck A has a velocity of 0.120 m/s to the left, and puck B has a velocity of 0.640 m/s to the right. 1)What was the speed of puck A before the collision? 2)Calculate the change in the total kinetic energy of the system that occurs during the collision. On a frictionless, horizontal air table, puck A (with mass 0.150 kg ) is moving toward puck B (with mass 0.400 kg ), which is initially at rest. After the collision, puck A has a velocity of 0.120 m/s to the left, and puck B has a velocity of 0.640 m/s to the right. 1)What was the speed of puck A before the collision? 2)Calculate the change in the total kinetic energy of the system that occurs during the collision.

Explanation / Answer

1)law of conservation of momentum....

m1u1 = -m1v1+m2v2......

u1 =1.58m/s ....right side

2)K.E before collision = 0.1889J......

K.E after collision =0.08084

change in K.E = 0.10806 J

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