1. If 2-Hz waves on a rope travels at 6 m/s, what is their wavelength? 2. If sou

Question

1. If 2-Hz waves on a rope travels at 6 m/s, what is their wavelength?

2. If sound waves travel at 340 m/s, what is the wavelength of a musical note with a frequency of 512 Hz?

3. If the speed of sound is 343 m/s, what is the lowest frequenc sound that will form a standing wave in a 2-m long tube with anti-nodes at both ends

4. If the speed of sound is 343 m/s, what is the lowest frequency sound that will form a standing wave in a 2-m long tube with a node at one end and an antinode at the other?

5. If the speed of the travelling waves on a 60 cm wire is 500 m/s, what is its fundamental frequency?

6. What is the fundamental frequency of an open organ pipe with a length of 1m?

7. How long would an open organ pipe need to be to produce a frequency of 400 Hz?

8. How long would a clsoed organ pipe need to be to produce a frequency of 400 Hz?

9. A concave mirror has a focal length of 30 cm. What kind of image is produced by an object located 60 cm from the mirror? Where is it located and what is its magnification?

10. A 15-cm ruler is palced 30 cm in front of a concave mirror with a focal length of 20 c,. Where is the image located and how big is it?

11. A 15-cm ruler is palced 75 cm from a converging lens with a focal length of 60 cm. Where is the image located and how big is it?

12. A tourist in Yellowstone National Park takes a photograph of a buffalo that is 40 m away and 2.2 m tall. If the lens has a focal length of 50 mm, how large is the image of the buffalo on the film?

13. Upon entering material X, light slows down by 30 percent compared to its speed in vacuum. What is the index of refraction of material X?

14. What is the thinnest soap film that will strongly reflect yellow light with a wave length of 589 nm?

Please show work and explain.

Explanation / Answer

1) v = lambda f

lambda = v/f = 6/2 = 3 m

2) lambda = 340/512 = 0.66 m

3) if antinodes at both ends lambda = 2 L = 4

f = 343/4 = 85.75

4)
now lambda = 4L = 8
f = 343/8 = 42.9 Hz

5) so lambda = 2 L = 1.2

f = 500/1.2 = 417 Hz

6) open pipe Lambda = 2L = 2m

f = v/lambda = 343/2 = 171.5 Hz

7) lambda = v/f = 343/400

length = lambda/2 = 343/800 = 0.429 m

8) now length = lambda/4 = 343/1600 = 0.214 m

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.