The two wires shown in Figure P19.38 carry currents of 5.00 A in opposite direct

Question

The two wires shown in Figure P19.38 carry currents of 5.00 A in opposite directions and are separated by 10.0 cm. Find the direction and magnitude of the net magnetic field at the following locations.

(a) at a point midway between the wires
T  ---Select--- to the left upward out of the page to the right into the page downward
(b) at point P1, 10.0 cm to the right of the wire on the right
T  ---Select--- to the right upward downward into the page out of the page to the left
(c) at point P2, 20.0 cm to the left of the wire on the left
T

Explanation / Answer

The formula that applies here is B = uI/2pir from each wire.

Part A)

Right in the middle, the B fields will add, and they are the same, so...

B = 2(4pi X 10-7)(5)/2pi(.05)

B = 4.0 X 10-5 T (40 uT) into the page

Part B)

At Point P1, the fields will subtract

B = (4pi X 10-7)(5)/2pi(.10) - (4pi X 10-7)(5)/2pi(.20)

B = 5 X 10-6 T (5 uT) Out of the page

Part C)

At Point P2, the fields will subtract

B = (4pi X 10-7)(5)/2pi(.20) - (4pi X 10-7)(5)/2pi(.30)

B = 1.67 X 10-6 T (1.67 uT) Out of the page

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