The primary coil of an ideal transformer is connected to a 120-V source and draw

Question

The primary coil of an ideal transformer is connected to a 120-V source and draws 1.0 A. The secondary coil has 900 turns and supplies an output current of 5.0A to run an electrical device.

Part A

What is the voltage across the secondary coil?

Express your answer using two significant figures.

Part B

How many turns are in the primary coil?

Express your answer as an integer.

Part C

If the maximum power allowed by the device (before it is destroyed) is 200W , what is the maximum input current to this transformer?

Express your answer using two significant figures.

Explanation / Answer

1.

From Transformer Turns Ratio

V1/V2=N1/N2=I2/I1

so

120/V2 =5/1

V2=24 Volts

b)

5/1 =N1/900

N1=4500 turns

c)

Input power =output power

Pinput=V1I1

200=120*I1

I1=1.7 A

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.