The primary coil of an ideal transformer is connected to a 120- source and draws

Question

The primary coil of an ideal transformer is connected to a 120- source and draws 1.0 . The secondary coil has 900 turns and supplies an output current of 12 to run an electrical device.

(a) What is the voltage across the secondary coil?
Express your answer using two significant figures.

(b) How many turns are in the primary coil?
Express your answer as an integer.

(c) If the maximum power allowed by the device (before it is destroyed) is 270 , what is the maximum input current to this transformer?
Express your answer using two significant figures.

Explanation / Answer

IP/IS=NS/NP==>1/12=900==>12*900=10800 turns on primary

VS/VP=NP/NS==>120*900/10800/900=10 V

a) 10 V

b) 10800

c) 270 W/120 Vrms2.25*23.2 Apeak==>if 120 V is peak than 270/1202.25 Apeak

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