PHYS HELP Consider the charge versus voltage graph of a capacitor given below ta

Question

PHYS HELP

Consider the charge versus voltage graph of a capacitor given below table. Calculate the capacitance of this capacitor from the charge vs voltage graph. If the actual capacitance is 2 mu F, find the percentage difference between the actual and experimental value. Figure below shows a 10 cm-diameter loop in three different magnetic fields. The loop's resistance is 0.11 Ohm . For each case, determine the induced potential difference, the induced current, and the direction of the current.

Explanation / Answer

A. apply Capacitance C = Q/V

C = -1/-0.49

C = 2.04 uC

% error = 4%

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induced emf e = NAdB/dt

e = 1* 3.14* 0.05 *0.05* 0.5

emf e =3.925 mVolts

induced cuurent i = emf./R = 3.925/0.11 = 0.03568 Amps

direction is clockwise

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induced emf e = NAdB/dt

e = 1* 3.14* 0.05 *0.05* 0.5

emf e =3.925 mVolts

induced cuurent i = emf./R = 3.925/0.11 = 0.03568 Amps

direction is counter clockwise

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induced emf e = NAdB/dt   or lvB

as tthere is no area providede, we may consider emf = 0

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