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Two point charges are placed on the x axis.( Figure 1 )The first charge, q 1 = 8

ID: 1272804 • Letter: T

Question

Two point charges are placed on the x axis.(Figure 1)The first charge, q1 = 8.00nC , is placed a distance 16.0m from the origin along the positive x axis; the second charge, q2 = 6.00nC , is placed a distance 9.00m from the origin along the negative x axis.

Part A

Find the electric field at the origin, point O.

Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures. Keep in mind that an xcomponent that points to the right is positive and a y component that points upward ispositive.

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Part B

Now, assume that charge q2 is negative; q2=?6nC. (Figure 2) What is the net electric field at the origin, point O?

Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures. Keep in mind that an xcomponent that points to the right is positive and a y component that points upward ispositive.

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Figure 1Figure 2 of 2

Two point charges are placed on the x axis.(Figure 1)The first charge, q1 = 8.00nC , is placed a distance 16.0m from the origin along the positive x axis; the second charge, q2 = 6.00nC , is placed a distance 9.00m from the origin along the negative x axis.

Part A

Find the electric field at the origin, point O.

Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures. Keep in mind that an xcomponent that points to the right is positive and a y component that points upward ispositive.

EOx,EOy =   N/C  

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Part B

Now, assume that charge q2 is negative; q2=?6nC. (Figure 2) What is the net electric field at the origin, point O?

Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures. Keep in mind that an xcomponent that points to the right is positive and a y component that points upward ispositive.

EOx,EOy =   N/C  

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Figure 1Figure 2 of 2

Explanation / Answer

Since both charges lie on the x axis the field will have no y component at the origin

E = k*q/r^2

q1 will produce a field to the left while q2 will produce one to the right

So Eox = k*q2/r2^2 - k*q1/r1^2 = 9.0x10^9*6.00x10^-9/9.0^2 - 9.0x10^9*8.0x10^-9/16.0^2

= 0.385N/C

Answer (0.385, 0)N/C

B) Now q2 produces a field to the left also

So Eox = -k*q2/r2^2 - k*q1/r1^2 = -9.0x10^9*6.00x10^-9/9.0^2 - 9.0x10^9*8.0x10^-9/16.0^2

= -0.948N/C

Answer (-0.948, 0)N/C

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